Emergency treatment of cardiac arrest victims sometimes involves injection of a

Question

Emergency treatment of cardiac arrest victims sometimes involves injection of a calcium chloride solution directly into the heart muscle.

1- How many grams of calcium chloride are administered in an injection of 5.0 mL of a 5.0 % m/v calcium chloride?

2- How many milliequivalents of calcium ion are injected in the 5.0 mL does?

3- What is the concentration of the 5.0% m/v calcium chloride solution in units of molarity?

4- What is the osmolarity of the 5.0% m/v calcium chloride solution?

5- If you put a red blood cell into this 5.0% m/v calcium chloride solution, explain what would happen to the cell during the process of osmosis and why?

Any help would be GREATLY appreciated!!

Explanation / Answer

1)

o find the % solution: (0.005 L * 0.05) = 2.5 x 10^-4 gram or 0.25 mgs

Now, to find the milliequivalents of Ca 2+, we need to find out how many milliequivalents per milligram then we can do the conversion.

mEq for Ca 2+= (40.0)/(2 x 1000)= 0.02 grams or 20 mgs

2)

0.25 mgs/ 20 mgs = 0.0125 mEq of Ca 2+

3) 0.05M

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