Chem - How do you add reactions 1 and 3? The net cell reaction is derived by add

Question

Chem - How do you add reactions 1 and 3?

The net cell reaction is derived by adding the anode half-cell reaction and the cathode half-cell reaction. In the chromium-silver voltaic cell, at the anode three electrons are lost by the one Cr(s) atom, and, at the cathode, one electron is gained by one silver ion. The oxidation half-cell reaction and reduction half-cell reaction for a chromium-silver voltaic cell are the following: anode (oxidation half-cell reaction): Cr(s) rightarrow Cr3+ (aq) + 3e- (1) cathode (reduction half-cell reaction): Ag+(aq)+e- rightarrow Ag(s) (2) Thus, the cathode half-cell reaction should be multiplied by a factor of 3 to equate the number of electrons transferred. Therefore, the cathode half-cell reaction will be 3Ag+(aq) + 3e- rightarrow 3Ag(s) (3) Now you can add reactions (1) and (3) to get the net cell reaction for the chromium-silver voltaic cell. Consider the reactions A + B rightarrow C and C + D rightarrow E. If you add these reactions the net reaction would be A + B rightarrow C C + D rightarrow E A + B + D rightarrow E

Explanation / Answer

since the number of elecrons on both sides are the same,

we get by adding,

3Ag+ + Cr(s) ---> Cr3+ +3Ag(s)

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