do locator assignment ssignmentSessiontoc Iron metal reacts widh chlorine gas gi

Question

do locator assignment ssignmentSessiontoc Iron metal reacts widh chlorine gas giving iro(I) chloride. The balanced chemical equation for this reaction is 2Fe(s) + 3Cb(g) 2 FeCl(s) Beginning with 29 0 g of iron, what mass of Cl, in grams, is required for complete reaction? What mass of FeCb can be produced? 842 g FeC Iron metal reacts with chlorme gas grung to n mchloride The balanced ch ital ng aton ir hist tos 2Fe(s) +3cldg 2FcCh(s) 84.2 g FeCl, can be produced from 29.0 g of iron and excess Cl,. If only 24.7 g of FeCl is obtained, what is the percent yield? Submit Answer Try Another Version 2 item attempts remaining 5 6 8 9

Explanation / Answer

c.

one equivalent iron will produce one equivalent of iron chloride

therefore 55.84 g of iron will produce 162.2 g of iron(III) chloride is 100 % yield

then 29 g of iron will produce how many gram of iron(III) chloride

55.84 g = 162.2 g

29 g = ?

by cross multiplying we will get theortical yield %

162.2 x 29 / 55.84 = 84.23 g of iron (III) chloride is theortical yield or 100 % yield

actual grams of iron (III) chloride produced = 24.7 g

then % yield = actual yield / theortical yield x 100 = 24.7 g / 84.23 g x 100 = 29.32 % is yield percentange obtained.

part d.

theortical yield or 100 % of NH3 is 181 g

actally obtained NH3 is 61.4 g

% yield = actual yield / theortical yield x 100

% yield = 61.4 g / 181 g x 100 = 33.92 %

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