lron metal reacts with chlorne gas giving iron(lil) chloride. The balanced chemi
ID: 711751 • Letter: L
Question
lron metal reacts with chlorne gas giving iron(lil) chloride. The balanced chemical equation for this reaction is 2 Fe(s)-3 C12(g) 2 FeCl3(s) Beginning with 26.0 g of iron, what mass of Cl2, in grams, is required for complete reaction? What mass of FeCl3 can be produced? 49.5 gCl2 75.5 g FeCl Iron metal reacts with chlorine gas giving iron II) chloride. The balanced chemical equation for this reaction is: 2 Fe(s)-3C12(g) 2 FeCl3(s) 75.5 g FeCl3 can be produced from 26.0 g of iron and excess Cl2. If only 21.3 g of FeClj is obtained, what is the percent yield? d Iron metal reacts with chlorine gas giving iron(III) chloride. The balanced chemical equation for this reaction is : 2 Fe(s)-3C12(g) 2 FeCl3(s) If 26.0 g each of iron and chlorine are combined, what is the theoretical yield of iron(III) chloride?Explanation / Answer
2Fe(s) + 3Cl2(g) ------------> 2FeCl3(s)
2 moles of Fe react with 3 moles of Cl2
2*56g of Fe react with 3*71g of Cl2
26g of Fe react with = 3*71*26/2*56 = 49.5g
2 moles of Fe react with Cl2 to gives 2 moles of FeCl3
2*56g of Fe react with Cl2 to gives 2*162.2g of FeCl3
26g of Fe react with Cl2 to gives = 2*162.2*26/2*56 = 75.5g of FeCl3
c. actual yiled = 21.3g
theoretical yiled = 75.5g
percnet yiled = actual yiled*100/theoretical yiled
= 21.3*100/75.5 = 28.2%
d. 2Fe(s) + 3Cl2(g) ------------> 2FeCl3(s)
no of moles Fe = w/G.A.Wt
= 26/56 = 0.464moles
no of moles of Cl2 = W/G.M.Wt
= 26/71 = 0.366 moles
2 moles of Fe react with 3 moles of Cl2
0.464 moles of Fe react with = 3*0.464/2 = 0.696 moles of Cl2 is required.
Cl2 is limiting reactant
3 moles of Cl2 react with Fe to gives 2 moles of FeCl3
0.366 moles of Cl2 react with Fe to gives = 2*0.366/3 = 0.244 moles of FeCl3
mass of FeCl3 = no of moles * gram molar mass
= 0.244*162.2 = 39.57g of FeCl3
The theoretical yiled of FeCl3 = 39.57g
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