Name It is estimated that there are about 37.2 trilion (3.72x . We are assuming

Question

Name It is estimated that there are about 37.2 trilion (3.72x . We are assuming that 30 trillion of these are red blood cells. Treat . A cell's DNA is contained only within the nucleus. . Red blood cells do not have a nucleus . Ba 10) cells in the body. e-pairs (bps) are the fundamental units of DNA and there is an estimat ed & Giga-bps the distance between base pairs is estimated to be 3.AA ( A-10 10m) The distance from the Earth to the Sun is about 149,597,870.7 km. 37. H 3.4 A 149,597,870 km ow many significant figures in each of the following measurements? trillion RBCs Count of 30 Count of 6 Gbps 38. Calculate the approximate length of DNA in the nucleus of one cell? (Answer in meters) 39. What is the length of DNA in a red blood cell. (Answer in meters) 40. Calculate the approximate sum length of DNA contained within all cells in the body. (Answer in kilometers) 41. Convert your answer to the previous question in to units of Sun-distances (i.e.the distance from the Earth to the Sun).

Explanation / Answer

37)

So, the number of significant figures in 3.4 oA is two.

So, the number of significant figures in count of 6 Gbps is infinite.

So, the number of significant figures in a count of 30 trillion RBCs is infinite.

So, the number of significant figures in 149,597,870 km is eight.

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