Known Find> Name: Show your work with units and Data and Observations ollowing q

Question

Known

Find>

Name: Show your work with units and Data and Observations ollowing questions and hand in at the start of your next class after lecture. correct significant figures for all questions that involve a calculation. figu Tube A Tube B Tube C Mass of tube & boiling chip Mass of tube, boiling chip and NaHCO Mass of tube, boiling chip and NaCl |/7 | 035 | 327 Mass of NaHCO Mass of NaCl Moles of NaCI Moles Nact Moles NaHCO3 Predicted (theoretical) 07m 125 . aooazne, u co38múla 5 moles of NaCt (use stoichiometry) o Mac Opo3 0.003x % Yield of NaCl

Explanation / Answer

balanced equation for the reaction is

1 mol NaHCO3 + 1 mol HCl yields 1 mol NaCl + 1 mol H2O + 1 mol Co2.

1:1 ratio is predicted

Our average for the three results was .97, which is decent.Wealso had one group with a 1:1 ratio. When we weighed the yielded product andcompared it to the original there was nearly a perfect ratio

We always run the risk of contaminated chemicals or underestimating theevaporation process.In each of these the ration would be greater than 1 so I thinkany occurred here.We could have also measured wrong which could be apossibility for our results being slightly low

Also theoretical Mole Ratio can be calculated as

NaHCO3 + HCl --> NaCl + H2O + CO2
The balanced equation tells you that the the ratio of NaHCO3 to NaCl moles is 1 : 1
20 g HCl = 0.55 moles HCl

NaHCO3(aq)+HCl(aq)CO2(g)+NaCl(aq)+H2O(l)

Mass and charge are balanced, so this is reasonable, and it specifies a molar equivalence of 1:1 with respect to NaCl:NaHCO3; i.e. there is a 1:1stoichiometry.

20 g NaHCO3 = 0.24 moles NaHCO3
mass / molar mass = moles

Related Questions

Navigate

• Browse (All)
• Browse K
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.