29. 3 CN-(aq) + 2 MnO4-(aq) + H2O() 2 MnO2(s) + 2 OH-(aq) + 3 CNO-(aq) In a titr

Question

29. 3 CN-(aq) + 2 MnO4-(aq) + H2O() 2 MnO2(s) + 2 OH-(aq) + 3 CNO-(aq) In a titration experiment CN-(aq) reacts with MnO4 (aq) as represented by the equation above. The dark purple MnO4(aq) solution is added from a buret to a colorless solution of CN(aq) in an Erlenmeyer flask. Which of the following best describes what happens to the pOH of the CN solution as the titration proceeds? (A) The 1- charge on the cyanide ions maintains the neutrality of the solution. (B) The reaction of water concentrates the solution, making it basic. (C) As OH ions are produced, the solution becomes more alkaline and the pOH increases. (D) As OH ions are produced, the solution becomes more alkaline and the pOH decreases

Explanation / Answer

Here the option D is correct and this can be explained as follows-

As the reaction proceeds,the CN- is converted into CNO- and the solution becomes alkaline as more OH- is produced.

Now as the pOH concerned,More value of pH indicates more basicity and we also know at 25 degree centigrade pH+pOH=14.Hence as pH is increased,pOH is decreased and decreased value of pOH indicates more basicity.

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