230g 58.4g 06.92 x 106 g QUESTION 16 iquld ammonia (boilig point -33.4*C) can be

Question

230g 58.4g 06.92 x 106 g QUESTION 16 iquld ammonia (boilig point -33.4*C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat 15.0g of NH3() from -55.0°C to-10.0°C specific heat, NH3 47ygK specific heat, NH3 2.2 J/g K heat of vaporization 23.5 kij/moll 2.15 k 037k) 21.5k 340 k 590 k QUESTION 17 S points A solution of 175 g of water and 106.1 g of an unkown solute has a frezing point of -3.3. Determine the molar mass of the unkown solute. Cick Save and Submit to save and submit. Click Save All Answers to sove all answers Save All Answers Save

Explanation / Answer

To bring NH3(l) at -55C to NH3 (g) at temp -10C, following energies will be required

Energy required here would be = specific heat x change in temp. x amount of NH3

= 4.7 j/g K x 21.6 x 15 g

= 1522.8 J or 1.52 kJ

Energy required here will be = heat of vaporisation x no. of moles of ammonia

= 23.5 kJ/mole x (15/18)

= 19.58 kJ

Energy required here would be = specific heat x change in temp. x amount of NH3

= 2.2 j/g K x 23.4 x 15 g

= 772.2 j or 0.77 kJ

Total energy required would be = 1.52 + 19.58 + 0.77 = 21.87 kJ

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