additional information: all sugars are 5% (added 50mL into flask) yeast solution

Question

additional information:

all sugars are 5% (added 50mL into flask)

yeast solution is 2% (added 50mL into flask)

time: 1 minute

2. For each of the sugars fermented by yeast, fill in the chart below to determine the mg of sugar consumed per minute during fermentation. You should have the answers for glucose from the multiple choice questions To calculate the moles of Co2 produced use the following equation, assuming P 1 atm. n = PV/RT where P is the atmospheric pressure in the lab, V is the volume in liters of CO2, n is the number of moles of CO2, R is the gas constant 0.082 L-atm/mole-Kelvin, and T is the temperature in Kelvirn. * To calculate the moles of sugar consumed use the following equation. m=n12s where m is the number of moles of sugar consumed, n is the number of moles of CO2 produced, and s is the number of simple sugars in that sugar. . To calculate the mg of sugar fermented per minute use the following equation. f= 1000mW / t where fis the mg of sugar fermented per minute, m is the number of moles of sugar consumed, w is the molecular weight of the sugar in g/mole, and t is the respiration time in minutes Calculations Table Moles of CO2 MW (g/mole) produced Moles of Sugar Consumed mg of sugar/min Sugar glucose fructose maltose maltotrlose

Explanation / Answer

Solution:

volume of CO2 produced

4.6-0.1=4.5ml

1.4-0.1= 1.3ml

5.3-0.1=5.2ml

1-0.1= 0.9ml

2-moles ofCO2 produced-n= PV /RT = V X P/RT= V x 1atm/ 0.082 Latm/K-mol x298K= V/24.436

n1=1.8x10^-4mol

n2=5.3x10^-5mol

n3=2.12x10^-4mol

n4=3.6x10^-5mol

moles of sugar consumed=moles of CO2 produced /2 xno of simple sugar in that sugar

1= 1.8x10^-4/2x1= 0.9x10^-4

2= 5.3x10^-5 /2x1= 2.65x10^-5

3=2.12x10^-2/2x2=0.53x10^-4

4= 3.6x10^-5 /2x3= 0.6x10^-5

mg of sugar /min=mol of sugar xmw x1000/5

1=0.9x10^-4x1000x 180 /5=3.24mg

2=2.65x10^-5 x1000 x180/5=0.0954mg

3=0.53 x10^-4 x1000 x342/5=3.625mg

4=0.6x10^-5 x1000x 504.4/5=0.6052mg

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