Enter Your Answer: 14.2 14.2 Correct The calculated value of the density of the

Question

Enter Your Answer: 14.2 14.2 Correct The calculated value of the density of the cube would also be subject to an uncertainty resulting from both the uncertainty in the measurement of mass, and the calculated maximum and minimum volumes Here, however, in order to simplify things we will calculate the maximum and minimum density values of the cube using only the actual mass. Therefore the uncertainty in the density is based only on the maximum and minimum volumes involved. Using the actual mass calculate the maximum density of the cube in units of g/cm Enter you answer to the correct number of significant figures Do not include units in your answer. Enter Your Answer: 0.7033 If the minimum density of the cube is 0.702, what is the range of densities of the cube? Enter you answer to the correct number of significant figures. .7033 Incorrect Do not include units in your answer. Enter Your Answer 001301 001301 Incorrect Accuracy of the 25 mL Pipet Here we look at the transfer pipet - a device constructed to deliver a precise fixed volume of liquid A common manufacturer's specification of the precision of a 25 mL pipet is ± 0.03 mL. A volume of

Explanation / Answer

Given length of edge = 2.44 + 0.02 cm

and weight = 10.46 + 0.01 g

In Question 4, they asked us to take actual mass i.e., 10.46 g

we have to calculate maximum density.of the cube.

The logic is, inorder to get maximum density, we should take minimum length.

Because density = mass / volume = mass /(length of the cube)3

So, mass = 10.46 g and length = 2.42cm

Hene density =mass /(length of the cube)3 = 10.46 /(2.42)3

= 10.46 / 14.17 = 0.738 g/cm3

or can be rounded off to two significant figures also as 0.74

Question 5

Given minimum density of cube = 0.702

In the above question 4, we got maximum density as 0.738

Range is the measure of dispersion.

so Range = maximum - minimum = 0.738 - 0.702 = 0.036

hence answe will be 0.036

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