8. You have assayed the activity of amylase under two separate NaCl concentratio

Question

8. You have assayed the activity of amylase under two separate NaCl concentrations. The starting concentration of your starch solution is 2 mg/ml, and you have conducted the assay as you did in lab. (1 point per question, total points 3) Time 0 10 mM Nac 1.47 1.41 50 mM NaCl 1.38 1.21 1.2 0.978 0.814 0.65 0.486 0.412 0.389 0.356 0.366 0.92 0.69 0.46 0.41 0.391 0.366 0.346 0.331 0.341 4 10 12 14 18 20 a. What is the starting amount of starch in these reactions in mg? 10mM 50mM b. What are the rates of these reactions (calculated as instructed in lab)? 10mM 50mM c. Under which condition is amylase activity highest? (choose one of the following) 10mM 50mM cannot be determined from these results

Explanation / Answer

1.from the table provided above we can get both of these data.

in 10mM - 1.47 in 50mM-1.38

2. rate is defined as change in concentration per unit time.

so, for 10mM rate=-deta c / deta t = -(1.41- 1.47)/ 2 = 0.03 M/s

for 50mM rate=-deta c / deta t = -(1.21-1.38)/2 = 0.085M/s

3. activity = rate * reaction volume

in 10mM activity = 0.03*15 = 0.45 mol/L

in 50mM activity = 0.085*15= 1.275mol/L

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