com/ibiscms/mod/ibis/view.php?id-6241954 PS Chapter 2-CHM-211 Lab Report Example

Question

com/ibiscms/mod/ibis/view.php?id-6241954 PS Chapter 2-CHM-211 Lab Report Example 1- 0 Ma Map Sapling Learning Two samples of sodium chloride were decomposed into their constituent elements. One sample produced 1.24 g of sodium and 1.91 g of chlorine. Which of the following could be the results of the decomposition of the other sample, being consistent with the law of constant composition (also called the law of definite proportions or law of definite composition)? O O O 4.28 g of sodium and 1.12g of chlorine 4.28 g of sodium and 856 g of chlorine 4.28 g of sodium and 6.59 g of chlorine 428 g of sodium and 2.57 g of chlorine O Prorous Check Answer 0 Next Est Hint

Explanation / Answer

law of constant composition states that a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

Atomc mass of sodium = 23gmol-1

Atomic mass of Chlorine = 35.5gmol-1

Molecular mass of NaCl = 23+35.5 = 58.5g/mol

% of Na = (23/58.5)x 100 = 39.3% = 39% (approx)

% of Cl =  (35.5/58.5)x 100 = 60.7% = 61% (approx)

Hence sodium chloride should contain 39% of sodium and 61% chlorine by mass.

so both samples of nacl also have the same composition of na and cl

for sample one

mass of NaCl = 1.24g +1.91g = 3.15g

% of Na = (1.24/3.15) x 100 = 39%

% of Cl = (1.91/3.15)x 100 = 61%

then the second sample will be the 4.28g Na and 6.59g Cl which have the same composition

%Na = (4.28/10.87)x100 = 39%

%Cl = (6.59/10.87)x100 = 61%

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