Can anyone help me with figuring out the theroetical yield, actual yield and % y

Question

Can anyone help me with figuring out the theroetical yield, actual yield and % yield of this equation? Between sodium benzoate turning into benzoic acid?

Quick recap of what I did during lab:

I started off with 2.00 g of sodium benzoate. Then I added 10 mL of DI water and then 5.0 mL of 3M HCl, I got a white substance and cooled down the solution and filterated through vacum filteration. I let the solid air dry and then placed it in an oven. The final mass of the dry product was 6.347 g of unknown substance

Explanation / Answer

Percentage of yield = (actual yield / theoretical yield ) * 100

Molar mass of sodium benzoate = 144.11 g/mol

2 g of sodium benzoate = 2 g / 144.11 g/mol => 0.01388 mol

Molar mass of benzoic acid = 122.12 g/mol

1 equivalent of sodium benzoate will produce 1 equivalent of benzoic acid ( sodium chloride will be dissolved in water).

Theoretical yield of benzoic acid = 0.01388 mol * 122.12 g/mol

= 1.69 g of benzoic acid

But your product weight is 6.347 g , actual yield cannot exceed theoretical yield. It should be less than 1.69 g.

Wash your product with distilled water for 3 times , then you will get rid off your impurities. Thereafter amounts will be lesser than that of 1.69 g.

% yield = ( xxx / 1.69 ) * 100

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.