A) how many miles of CaCO3 are in the sample?(formula mass=100.1) B.) what is th

Question

A) how many miles of CaCO3 are in the sample?(formula mass=100.1)
B.) what is the molarity if the Ca ion in the 250 ml of solution?
C.) how many moles of Ca ion are in a 25.00 ml aliquot if the solution? Section Experiment 8 ADVANCE STUDY ASSIGNMENT 1. A0.5118-g sample of CaCo,is dissolved in 6MHCI,and the resulting solution is diluted to 2500mlin a volumetric flask a. How many moles of CaCO, are in the sample? (formula mass 100.1) OOS 113 moles 1 00. 1 b. What is the molarity of the Ca2 ion in the 250 ml of solution? moles of Sotutt Ca c. How many moles of Ca" ion are in a 25.00-ml aliquot of the solution? moles 2. 25.00-ml aliquots of the solution from Problem 1 are titrated with EDTA to the Calmagite end-point. An aliquot is found to require 28.55 ml of the EDTA before the solution becomes sky blue. a. How many moles of EDTA are there in the volume that is used? moles b. What is the molarity of the EDTA solution? A 100-ml sample of hard water is titrated with the EDTA solution in Problem 2. The volume of EDTA required to reach the end-point is 22.44 ml. a. How many moles of EDTA are used in the titration? 3. moles How many moles of Ca ion are there in the I moles c. If the Ca ion comes from CaCO, how many moles of CaCO, are there in 1 liter of the hard water? How many grams CaCO, per liter? moles grams d. If I ppm CaCO,-1 mg per liter, what is the water hardness in ppm CaCO,?

Explanation / Answer

given

mass of sample m=0.5118 g

total volume V=250 ml

number ofmoles of compound =number of moles of calcium=weight/molecular weight

=0.5118/100.1 =0.005113

molarity of calcium =number of moles of calcium/volume of solution=0.005113/0.250

=0.020452 M

number of moles in 25 ml=molarity*volume =0.020452*0.025=0.0005113 moles

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