1. Calculate and report the average mass of the polyethylene disk and flask. Inc

Question

1. Calculate and report the average mass of the polyethylene disk and flask. Include theabsolute error in your reported values, that is, report your results as the avg. mass ± absolute error and include units

2. What are the percent errors in the mass of the polyethylene disk and flask?

3. How do the magnitudes of the absolute errors for the polyethylene disk and flask compare? How do the percent errors compare? Based on these comparisons, what can you say about the reliability of the balances that were used?

Weight in grams

Flask: 77.571, 77.610. 77.620, 77.610, 77.615, 77.615

Disc: 0.299, 0.301, 0.301, 0.303, 0.299, 0.300

Explanation / Answer

FOR POLYETHENE DISK:-

AVG. MASS=(0.299+0.301+0.301+0.303+0.299+0.300)/6=0.3005gm

IF Di REPRESENTS ABSOLUTE ERROR IN i'th MEASUREMENT OF MASS OF DISC

ABSOLUTE ERROR=MOD{Di(MEASURED)-Di(TRUE/AVG)}:-

%ERROR=(ABSOLUTE ERROR/MEASURED VALUE)*100

ABSOLUTE ERROR IN D1=MOD(0.299-0.3005)=0.0015gm

% ERROR IN D1=0.0015/0.299*100=0.501%

ABSOLUTE ERROR IN D2=MOD(0.301-0.3005)=0.0005gm

  % ERROR IN D2=0.0005/0.301*100=0.166%

ABSOLUTE ERROR IN D3=MOD(0.301-0.3005)=0.0005gm   

% ERROR IN D3=0.0005/0.301*100=0.166%

ABSOLUTEERROR IN D4=MOD(0.303-0.3005)=0.0025gm

   % ERROR IN D4=0.0025/0.303*100=0.825%

ABSOLUTE ERROR IN D5=MOD(0.299-0.3005)=0.0015gm

   % ERROR IN D5=0.0015/0.299*100=0.502%

ABSOLUTE ERROR IN D6=MOD(0.300-0.3005)=0.0005gm   

% ERROR IN D6=0.0005/0.3*100=0.167%

TOTAL ERRORS=(0.0015+0.0005+0.0005+0.0025+0.0015+0.0005)=0.007gm

TOTAL PERCENTAGE ERROR=2.327%

AVG MASS OF POLYETHYLENE DISK=(0.3005±0.007)gm

FOR FLASK:-

AVG. MASS=(77.571+77.610+77.620+77.610+77.615+77.615)/6=77.607gm

IF Fi REPRESENTS ABSOLUTE ERROR IN i'th MEASUREMENT OF MASS OF FLASK

ABSOLUTE ERROR=MOD{Fi(MEASURED)-Fi(TRUE/AVG)}:-

%ERROR=(ABSOLUTE ERROR/MEASURED VALUE)*100

ABSOLUTE ERROR IN F1=MOD(77.571-77.607)=0.036gm

% ERROR IN F1=0.036/77.571*100=0.046%

ABSOLUTE ERROR IN F2=MOD(77.610-77.607)=0.003gm

% ERROR IN F2=0.003/77.610*100=0.00387%

ABSOLUTE ERROR IN F3=MOD(77.620-77.607)=0.013gm

% ERROR IN F3=0.013/77.620*100=0.0167%

ABSOLUTE ERROR IN F4=MOD(77.610-77.607)=0.003gm

% ERROR IN F4=0.003/77.610*100=0.00387%

ABSOLUTE ERROR IN F5=MOD(77.615-77.607)=0.008gm

% ERROR IN F5=0.008/77.615*100=0.01031%

ABSOLUTE ERROR IN F6=MOD(77.615-77.607)=0.008gm

% ERROR IN F6=0.008/77.615*100=0.0103%

TOTAL ABSOLUTE ERRORS=0.071gm

TOTAL PERCENTAGE ERRORS=0.09105%

AVG. MASS OF FLASK=(77.607±0.071)gm

CLEARLY,MAGNITUDE OF ABSOLUTE ERRORS FOR FLASK IS MORE THAN POLYETHYLENE DISK.BUT,PERCENTAGE ERROR FOR POLYETHYLENE IS MORE THAN THAT OF FLASK.

RELIABILITY RELATES TO ACCURACY.ACCURACY HERE REFERS TO THE TOLERANCE LEVEL IN THE MEASURING OF MASSES.SO,THE FLASK IS MORE RFELIABLE.

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