5. For the acid, base reaction shown below, complete the equation by filling in
ID: 715463 • Letter: 5
Question
5. For the acid, base reaction shown below, complete the equation by filling in the spaces with the conjugate acid calculate the equilibrium constant (K) for this reaction. CH4 acid base conjugate base conjugate acid pKa pKa b. For the acid, base reaction shown below, complete the equation by filling in the spaces with a base and its conjugate acid such that the equilibrium constant is greater than 10. In addition, calculate the equilibrium constant (K) for your specific base. OCN acid conjugate base conjugate acid pKa c. Trifluoroethanol (CF CH OH, pKa 12.) is more acidic than ethanol (CH,CH OH, pKa 16). Providea Provide a three-dimensional structure for each conjugate base and draw the orbitals for all lone pairs. succinct explanation for the greater acidity of trifluoroethanol.Explanation / Answer
H20 +CH3 ^- = OH^- + CH4 , K = [OH ^ -] * [CH4] / [H2O] *[ CH3 ^-]
HCN + H2O = CN^- + H30^+ ,K = [CN^-] + [ H3O ^+] / [ HCN]* [H2O]
Trifluroethanaol is more acidic than ethanol because the conjugate base that is produced from trifluroethanaol after elimination of H+ is stabilized by electron withdrawing inductive effect of fluorine. However in the case of ethanol no such stabilization effect is present in the conjugate base.Hence,the conjugate base of trifluroethanaol is formed at a faster rate thereby making trifluroethanaol more acidic in nature.
CF3CH2OH = CF3CH2 ^- + H ^+
CH3CH2OH = CH3CH2^- + H^+
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