Elemental Analysis and Empirical Formula The class of ternary compounds called c

Question

Elemental Analysis and Empirical Formula The class of ternary compounds called carboranes (containing the elements carbon, boron and hydrogen) have played a prominent role in many areas of fundamental chemical research. In particular, they have provided many interesting examples for testing theories on chemical bonding and structure. A particular carborane has the following mass percentages: 70.89%B and 22.50%C. What is the empirical formula of this compound? Choose appropriate coefficients in the formula below CBH

Explanation / Answer

we have mass of each elements as:

C: 22.5 g

B: 70.89 g

H: 100 - 22.5 - 70.89 = 6.61 g

Divide by molar mass to get number of moles of each:

C: 22.5/12.01 = 1.8734

B: 70.89/10.81 = 6.5578

H: 6.61/1.008 = 6.5575

Divide by smallest:

C: 1.8734/1.8734 = 1

B: 6.5578/1.8734 = 3.5

H: 6.5575/1.8734 = 3.5

Multiply by 2 to get simplest whole number ratio:

C: 1*2 = 2

B: 3.5*2 = 7

H: 3.5*2 = 7

So empirical formula is:C2B7H7

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