3. Using the data in the table below, Oxidant Reductant n | E,o (V) 2 -0.23 2+0.

Question

3. Using the data in the table below, Oxidant Reductant n | E,o (V) 2 -0.23 2+0.82 Iml glutathione (oxidized) glutathione (reduced) 02 + 2H+ H2O Note: Eo is the standard redox potential at standard conditions. Eo refers to the partial reaction written as: oxidant + e- reductant a. Write the half reactions for the two reactions in the able. b. Write the overall reaction for the oxidation of reduced glutathione by O2 c. Calculate and AG" for this reaction. d. In which direction does the reaction proceed?

Explanation / Answer

Part a

The two half cell reactions are

Oxidation reaction

Glutathione (reduced) = glutathione (oxidized) + 2e-

Eox = 0.23 V

Reduction reaction

1/2 O2 + 2H+ + 2e- = H2O

Ered = 0.82 V

Part b

Overall cell reaction

Glutathione (reduced) + 1/2 O2 + 2H+ + 2e- = H2O + glutathione (oxidized) + 2e-

Glutathione (reduced) + 1/2 O2 + 2H+ = glutathione (oxidized) + H2O

Part c

E° = Eox + Ered

= 0.23 + 0.82

= 1.05 V

G° = - nFE°

= - 2 x 96500 C/mol x 1.05 V

= - 202650 J/mol x 1kJ/1000 J

= - 202.65 kJ/mol

Part d

G° < 0

In the forward direction, the reaction proceeds

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