Formaldehyde (HCHO) is produced by partial oxidation of methanol (CH3OH). Severa

Question

Formaldehyde (HCHO) is produced by partial oxidation of methanol (CH3OH). Several reactions also occur, producing formic acid (HCOOH), CO, CO2, and H2O. Suppose 100kgmol/h methanol and 20 kgmol/h O2 are fed to a reactor, where 40% of the methanol and 95% of the O2 is converted to products. What must the reactor outlet composition be? Formaldehyde (HCHO) is produced by partial oxidation of methanol (CH3OH). Several reactions also occur, producing formic acid (HCOOH), CO, CO2, and H2O. Suppose 100kgmol/h methanol and 20 kgmol/h O2 are fed to a reactor, where 40% of the methanol and 95% of the O2 is converted to products. What must the reactor outlet composition be?

Explanation / Answer

ANSWER:

Basis: 1 hour of process

Quantity of methanol in nourish 100 kg molls

Amount of oxygen 21.05 kgmols

Amount of formalihyde produced (assuming as per main reply) = (O2 moles) (Moles of formaldihyde shaped per mole of O2) ( proportion convertion)=21.05*2*0.95= 39.995

Oxygen unreacted =1.0525

Methanol un react =100-40= 60

By crop fromed or due to side reaction of methnol use of 0.005 mols

Therefore manufactured goods concentration are HCHO 40% O2 1% and Methnol 60%.

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