This is all the information that the teacher gave us H2 at 0.2 bar, pH=9.2 O2 at
ID: 718523 • Letter: T
Question
This is all the information that the teacher gave usH2 at 0.2 bar, pH=9.2
O2 at 1.1 bar, pH=2.4
Explanation / Answer
This is all the information that the teacher gave us H2 at 0.2 bar, pH=9.2 O2 at 1.1 bar, pH=2.4 Calculate Cell Potential? ANSWER: Step 1: pH of H2 = 9.2 so [H+] = 10^(-9.2) = 6.31 x10^-10M pH of O2 = 2.4 so [H+] = 10^(-2.4) = 3.98 x10^-3M O2 is gas. The pressure of O2 is 1.1 bar or (1.1bar x0.986 atm/bar) = 1.0846 atm. Step 2 : Equation. O2(g) + 4 H+(aq) + 4 e- --> 2 H2O(l) Eo(reduction) = + 1.229 V Step 3: Formula. Q = 1/(Pressure(O2)x [H+]^4) Q = 1/((1.0846 atm) x(6.31 x10^-10M)^4) = 0.922/1.585x10^-37 = 5.81 x10^+36 Step 4: Ecell = EoCell - (RT/nF) ln Q or Where n is number of transfered electrons. here it is 4. Ecell = Eocell - (0.0592/n) log Q = +1.229 V - ((0.0592/4) log(5.81 x10^+36) = +1.229 V-0.0148 log(5.81 x10^+36) = +1.229 V-(0.0148 x 36.76)V = +1.229 V-0.544 V = The Ecell value is +685 V.
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