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at 350 degrees celcius and 200 atm the % yield is 50%. Calculate how many grams

ID: 718587 • Letter: A

Question

at 350 degrees celcius and 200 atm the % yield is 50%. Calculate how many grams of N gas are required to produce 25.000g Ammonia?

Explanation / Answer

N2 +3H2 --> 2NH3 so, 1 mole nitrogen is needed for 2 moles of ammonia, but two atoms of nitrogen give nitrogen for two ammonia molecules we could convert to grams and back, but here is a shortcut since we are going from nitrogen to nitrogen (plus 2H's) 25 g ammonia is 14/17 nitrogen (14/17)25g = 20.59g, this would be the answer if we had 100% yield. Since yield is half this, we need twice as much, 41.18g