Magnesium hydroxide (Mg(OH)2) reacts with hydrochloric acid to produce magnesium

Question

Magnesium hydroxide (Mg(OH)2) reacts with hydrochloric acid to produce magnesium chloride and water. How many liters of 0.8 M HCl react with 0.25 grams of magnesium hydroxide?

Explanation / Answer

Mg(OH)2(s) + 2HCl(aq) >>>>>>>>>>>>>>> MgCl2(aq) + 2H2O(l) grams HCl required = (0.25 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 0.31 Litres HCl required Since there are only 0.8 M HCl, then HCl is the limiting reactant. theoretical yield MgCl2 = (0.8 M HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 1.04 grams MgCl2

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