A 25.0 mL bubble is released from a divers tank at a pressure of 4.00 atm and a

Question

A 25.0 mL bubble is released from a divers tank at a pressure of 4.00 atm and a temperature of 10.5 degreesC.
Show how to determine and calculate the volume of the bubble when it reaches the surface where the pressure
is 0.998 atm and the temperature is 19.5 degreesC?
Would you use Boyle's Law or Charles's Law to solve this or am I way off here.
I got 100.2 mL with Boyle's V2= P1xV1/P2 = 4.00x25.0/0.998
And 25.8 mL with Charles's Law V2= V1xT2/T1= 25.0x293/284 (changing the temp's to Kelvin)

Explanation / Answer

using the relation P1*V1/T1 = P2*V2/T2 we have V2 = 25*4*292.5/(283.5*0.998)=> V2 = 103.38 mL

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