Iron(III) oxide reacts with carbon monoxide to produce iron and carbon; Fe2O3(s)

Question

Iron(III) oxide reacts with carbon monoxide to produce iron and carbon; Fe2O3(s)+3CO(g)-->2Fe(s)+3CO2(g). a) What is the percent yield for the reaction if 65.0 g of iron(III) oxide produced 15.0 g of iron? b) What is the percent yield for the reaction if 75.0 g of carbon monoxide produces 85.0 g of carbon dioxide?

Explanation / Answer

Fe2O3(s)+3CO(g)-->2Fe(s)+3CO2(g) a) moles of Fe = 65/159.68 = 0.41 moles moles of Fe produced = 0.41 x 2 = 0.82 moles or, 45.59 g of Fe. But fe produced = 15 g Thus, %yield = 32.90% b)moles of CO = 75/28 = 2.68 moles moles of CO2 produced = 2.68 moles or, 117.86 g of Fe. But fe produced = 85 g Thus, %yield = 72.12%

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