If 10.0 mL of 0.100 M HCl is titrated with 0.200 M NaOH, what volume of sodium h

Question

If 10.0 mL of 0.100 M HCl is titrated with 0.200 M NaOH, what volume of sodium hydroxide solution is required to neutralize the acid?

HCl(aq) + NaOH(aq) ---> NaCl(aq) + H2O(l)

please include easy steps to follow as I have not done titrations, thanks!

Explanation / Answer

ANSWER: Balance the equation: NaOH + HCl --------> NaCl + H2O Neutralization Formulae: Ma Va/na = Mb Vb/nb Where Ma = Molarity of acid, Va = Volume of acid, na = Coefficient of acid in balanced equation. Mb = Molarity of base, Vb = Volume of base, nb = Coefficient of base in balanced equation. (10.0 mL x 0.100 M HCl )/1 = (0.200 M NaOH x Volume of NaOH)/1 Volume of NaOH = 5 ml.

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