For the following reaction, 5.75 grams of potassium hydroxide are mixed with exc

Question

For the following reaction, 5.75 grams of potassium hydroxide are mixed with excess phosphoric acid. The reaction yields 6.61 grams of potassium phosphate.

potassium hydroxide (aq) + phosphoric acid (aq) potassium phosphate (aq) + water (l)

What is the theoretical yield of potassium phosphate ? ___?___grams

What is the percent yield of potassium phosphate ? ___?___%

Explanation / Answer

The balanced reaction is 3 KOH + H3PO4 =======> K3PO4 + 3 H2O Moles = mass/molar mass Moles of KOH = 5.75 g/56.11g/mol = 0.10 mol Koh Here the molar ratio is 3 KOH : 1 K3PO4 0.10 mol KOH * (1 mol K2PO4/3 mol KOH)*(212.27 g K3PO4/1 mol K3PO4) 7.25 g K3PO4 [ Theoretical yield] % of yield = actual /theroretical * 100 % of yield = (6.61/7.25)*100 = 91.17%

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