Given the following thermochemical equation ( 1 and 2), calculate the value of D

Question

Given the following thermochemical equation ( 1 and 2), calculate the value of DELTA H in kJ for reaction 3.

(1) S+ O2 ->SO2 DELTA H = -296.1 kJ

(2) SO3 -> SO2+ 1/2 O 2 DELTA H = 99.10 kJ

(3) 2S+ 3O2 ->2SO DELTA H = kJ

Delta H for equation 3 is ?

Explanation / Answer

S+ O2 ->SO2 DELTA H = -296.1 kJ multiplying * 2 2 S + 2 O2 =====> 2SO2 H = -592 Kj------------------------(1) SO3 -> SO2+ 1/2 O 2 DELTA H = 99.10 kJ SO2+ 1/2 O 2 ==> SO3 H = -99.10 Kj ---- multiply by 2 2SO2 + O2 =====> 2 SO3 H = 198.2 Kj--------------------> (2) Adding (1) and (2) 2S+ 3O2 =======> 2SO3 H = -592+(-198.2) = 790.2 KJ [SO2 get can celled]

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