I need the equation for the formation of the second tripeptide Solution for the

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for the formation of second tripeptide, lets see In the stated order (valine + alanine + serine), you have the following formulas: Valine (Val): (CH3)2CH-CH(NH2)-COOH Alanine (Ala): CH3-CH(NH2)-COOH Serine (Ser): HOCH2-CH(NH2)-COOH For the reaction of valine and alanine, you will get the following (excuse the dots -- this is a bad program for drawing): H3C.........NH2 ................| .........CH-CH-COOH [Val] + ......../ H3C ............NH2 ............| + CH3CH-COOH [Ala] ---> H3C.........NH2..........CH3 ............. ...|.................| ........CH-CH-C-NH-CH-COOH [Val-Ala] ......../..............|| H3C..............O + H2O Now take this dipeptide (Val-Ala), and react it with Serine: H3C.........NH2..........CH3 ............. ...|.................| ........CH-CH-C-NH-CH-COOH [Val-Ala] + ......../..............|| H3C..............O .................NH2 .................| HOCH2-CH-COOH [Ser] ---> H3C...NH2...........CH3.........CH2OH.… .....|......|..................|......… ..HC-CH-C-NH-CH-C-NH-CH-COOH .....|...........||.................|| H3C........O................O + H2O

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