Under certain conditions, the following reaction: 2NH3(g) ? N2(g)+ 3H2(g) Has a
ID: 726035 • Letter: U
Question
Under certain conditions, the following reaction:2NH3(g) ? N2(g)+ 3H2(g)
Has a KP of 1.6 x 103. If at equilibrium, PH2 = 0.25 atm and PNH3 = 2.4 x 10-3
atm, what is the equilibrium pressure of N2?
To solve this problem, we first write the KP expression for the reaction. We can
then substitute in the equilibrium constant value, and the known equilibrium
partial pressures, and solve for our unknown partial pressure
Can someone help in finding the value of N2? and show how to set up to find missing value?
The answer:
PN2 = 0.59 atm
Explanation / Answer
Kp=[N2][H2]^3/[NH3]^2 Solving this put the values of pressure of NH3 and H2 we get [N2]=0.59 atm Hey rate me lifesaver this time,I am the same wo answered previously :) N yeah if you need anymore help , you are most welcome :)
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