Nitrogen gas may react with hydrogen gas to form hydrazine gas, N2H4, according

Question

Nitrogen gas may react with hydrogen gas to form hydrazine gas, N2H4, according to the reaction N2 + 2 H2 ---> N2H4. 10 L of N and 25 L H react to completion (the limiting reagent is converted entirely to hydrazine). What volume of the hydrazine gas will be produced if pressure and temperature are held constant? (Hint: Identify the limiting reagent and calculate the volume of the un-reacted excess reagent.)

Please do no copy/paste from other sites and answers. I would appreciate it if steps could be shown. Thanks in advance!v

Explanation / Answer

The ratio of the reactants are 1 :2. So the limiting reactant would be 10L of Nitrogen gas. Step 1: 10L N2 gas x (1mol H2/1mol N2) = 20 L H2 gas. Because 10L N2 gas is needed 20L of Hydrogen gas only to complete the reaction but we have 25 L ( 25-20=5L excess) H2 gas. Step 2: Moles ratio of N2 and N2H4 gases are 1 :1 10L N2 gas x (1mol N2H4/1mol N2) = 10 L N2H4 gas.

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.