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Got a question for my lab hw and i dont know what to do, please help. For each u

ID: 728042 • Letter: G

Question

Got a question for my lab hw and i dont know what to do, please help.

For each unknown liquid, record the following:

the percent deviation of each substance, given by:

percent deviation = |(measured value) - (literature value)| / |(literature value)| * 100%


For the whole lab all i had to do is record the melting point and boiling point of certain liquids (with only 5ml of liquid in the test tube) for example i got for Benzene the melting point 5.49 and its boiling point 80.09. I have no idea how to solve and i have 4 more liquids to get the percent deviation. If any one can explain it to me so i can do the rest I would highly appreciated thank you!








Explanation / Answer

you are just expected to calculate the % deviation. It is easy and there is no need to worry. for the example you have given above, here is a sample calculation: you measured the melting point and boiling points of benzene to be 5.49 and 80.09 respectively. now look up the melting and boiling point of benzene from a reputed source (say wiki) I have found them for you. as per wiki, Melting point of benzene = 5.5 deg C boiling point of benzene = 80.1 deg C these above two values are literature values. and what you found out are measured values. so % deviation in melting point = (|5.49-5.5|/|5.5|)*100 = 0.182% boiling point = (|80.09-80.1|)/(|80.1|)*100 = 0.0125% see !! it is simple. you already have your measured values, just look up the internet for literature value and put it in formula. and the best part is, the answer will always be positive ;) , since there is a modulus operator in the formula. so there is no confusion for having +ve/-ve answers. for sure all answers are positive. so go ahead and complete your hw ;) :D

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