Given the following information A + B rightarrow 2D Delta H degree = 791.7 kJ De

Question

Given the following information A + B rightarrow 2D Delta H degree = 791.7 kJ Delta S degree = 344.0 J/K C rightarrow D Delta H degree = 482.0 kJ Delta S degree Delta s degree = - 221.0 J/K calculate Delta G degree for the following reaction at 298 K. A + B rightarrow 2C Delta G degree =

Explanation / Answer

A+B-->2D ....(1) C-->D.........(2) eq(1) - 2times eq(2) is A+B-->2C hence resultant delta H= 791.7-(2x482) = -173 KJ resultant delta S = 344-(2x(-221)) = 786 J/K = 0.786 KJ/K we have delta G= delta H - T delta S i.e dG=dH-TdS hence resultant Delta G = -173 - 298(0.786) = -407.228 KJ

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