You are studying fruit flies that have a metabolic disorder. An enzyme assay is

Question

You are studying fruit flies that have a metabolic disorder. An enzyme assay is available to determine the level of the enzyme in tested flies. Flies that are EE are scored as 1.0 (100% activity), flies that are Ee are scored as 0.5 (50% activity), and flies that are ee are scored as 0.0 (0% activity).

Two Ee flies mate and you test the enzyme activity of all of their progeny. Here are the results:

29

For this cross, how many flies do you expect would have an enzyme activity of 0.5?

a) 70

b)60

c)50

d)40

e)30

29

Explanation / Answer

Total number of flies is 120; when Ee crossed with Ee, 1:2:1 ratio is expected. So, expected number of flies having 0.5 activity will be 1/2 of the total, i.e. 60

b) is the correct option.

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