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2.a) What is the oxidation state of iron in Fe(NH4)2(SO4)2 X 6H2O? Justify your

ID: 730794 • Letter: 2

Question

2.a) What is the oxidation state of iron in Fe(NH4)2(SO4)2 X 6H2O? Justify your answer

b.) Is the iron being oxidized or reduced in the reaction in question 1?

6.)In the following balanced equation, AB is the only colored species. All other species/reagents are colorless. If the goal of an experiment is the determination of the percentage of D in an impure sample of the salt, MD and the experiment technique to combine reagents for this determination is a titration, identify the reagent that will form the titrant? Justify your answer.

Equation: AB + D- > AD + B-

Explanation / Answer

H is +1 and O is -2. Then there are the known ion groups, ammonium, NH4, is +1 and sulfate, SO4 is -2. From that you can figure out what the oxidation numbers are for S (4 x -2 is -8 so the S must be +6 to give an overall ox. no. of -2) and for N (4 x 1 is +4 so N must be -3 to give you an overall charge of +1). The only one left is Fe, so with 2 x +1 for ammonium and 2 x -2 for sulfate, you get the charge for Fe at +2.