E) Calculate [OH^-] for 1.00mL of 0.220M NaOH diluted to 1.50L . F) Calculate pH

Question

E) Calculate [OH^-] for 1.00mL of 0.220M NaOH diluted to 1.50L .

F) Calculate pH for 1.00mL of 0.220M NaOH diluted to 1.50L

Explanation / Answer

E) 0.220M NaOH * 0.001L = 0.00022 mol NaOH --> / 1.5L = 1.46e-4 M NaOH F) pH + pOH = 14, pOH = -log[OH]. Therefore, -log(1.46e-4)=pOH = 3.84. Therefore pH = 14-3.84 = 10.16 G) 0.2M NaOH * 0.006L = 0.0012 mol NaOH = 0.0012 mol OH 7.5e-2 M Ca(OH)2 * 0.02L = 0.0015 mol Ca(OH)2 = 0.003 mol OH 0.0012+0.003 = 0.0042 mol OH total, 0.02+0.006 = 0.026L solution 0.0042 mol OH / 0.026L = 0.162M OH H) pH = 14 - (-log(0.162)) = 13.21

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