(a) Consider the combustion of ether, given below: 1 C4H10O(g) + 6 O2(g) 4 CO2(g

Question

(a) Consider the combustion of ether, given below:
1 C4H10O(g) + 6 O2(g) 4 CO2(g) + 5 H2O(g)
If C4H10O(g) is decreasing at the rate of 0.960 mol/s, what are the rates of change of O2(g), CO2(g), and H2O(g)?


Delta O2(g)/t = mol/s


Delta CO2(g)/t = mol/s


Delta H2O(g)/t = mol/s


(b) The decomposition reaction given below:
2 NOCl(g) 2 NO(g) + 1 Cl2(g)
is carried out in a closed reaction vessel. If the partial pressure of NOCl(g) is decreasing at the rate of 408 torr/min, what is the rate of change of the total pressure in the vessel?

Explanation / Answer

O2 = decreasing at the rate of 5.76 mol/s CO2 = Increasing at the rate of 3.84 mol/s H2O = increasing at the rate of 4.8 mol/s b) Rate of Change of Total Pressure = 408 + 204 - 408 = 204 The pressure is Increasing at the rate of 204 torr/min

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