Taken from Chapter 15 Problem # 66 Solution and Setup please. In a bomb calorime

Question

Taken from Chapter 15 Problem # 66

Solution and Setup please.

In a bomb calorimeter compartment surrounded by 945 g of water, the combustion of 1.048 g of benzene, C6H6( ), raised the temperature of the water from 23.640degreeC to 32.692degreeC. The heat capacity of the calorimeter is 891 J/degreeC. (a) Write the balanced equation for the combustion reaction, assuming that C02(g) and H20( ) are the only products, (b) Use the calorimetric data to calculate dalta E for the combustion of benzene in kj/g and in kj/mol.

Explanation / Answer

a)2C6H6 +15O2 -----> 12CO2 + 6H2O b) delta E = 891x (32.692-23.64) x10^-3 kJ/1.048 g = 7.6959 KJ/g 1.048 gms =1.048/(12x6+6) moles = 0.0134589 moles delta E = 891x (32.692-23.64) x10^-3 kJ x 78/1.048 mol =600.2823 KJ/mol

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