What is the percent yield of a reaction in which 258 g phosphorus trichloride re

Question

What is the percent yield of a reaction in which 258 g phosphorus trichloride reacts with excess water to form 120. g HCl and aqueous phosphorous acid (H3PO3)?
............ %

Explanation / Answer

First write out and balence the reaction equation: Fe2O3 + 2Al ==> Al2O3 + 2Fe Second, look for the necessary molar masses: Al: 26.98 g/mol, and Fe: 55.845 g/mol. Third, find the theoretical yield. So we started with 258 g of aluminum, or 258/26.98 = 9.563 mole of aluminum. Since the reaction equation indicates that one mole of aluminum react should produce a theoretical one mole of iron, we theoretically should have 9.563 mole of iron, or 9.563*55.845 = 534.0 g of iron. Finally, we calculate the percent yield: 464/534.0 = 86.9% Now, please solve the second one, for which you already have the balenced reaction equation.

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