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If one mole of each is dissolved in 1.00 L of water, which will lower the vapor

ID: 737176 • Letter: I

Question

If one mole of each is dissolved in 1.00 L of water, which will lower the vapor pressure the most?
a. C12H22011
b. NaNO3
c. C3H7OH
d. MgCl2

Explanation / Answer

answer D (a) Sucrose (C12H22O11) 1.0 M C12H22O11 C12H22O11(s) -----> C12H22O11(aq) Molecular dissolving 1.0 M ............................. 1.0 M (Total effect = 1.0 M) (b) Sodium nitrate (NaNO3) 1.0 M Na2SO4 NaNO3(s) ------> Na^+(aq) + NO3^-(aq) Ionic dissolving 1.0 M .................. 1.0 M ........ 1.0 M (Total effect = 2 M) (c) Propyl alcohol (C3H7OH) 1.0 M C3H7OH C3H7OH(l) -----> C3H7OH(aq) Molecular dissolving 1.0 M ............................. 1.0 M (Total effect = 1.0 M) (Although its total effect is 1.0 M like sucrose, propyl alcohol is a volatile liquid, it increases the vapor pressure) (d) Magnesium chloride (MgCl2) 1.0 M MgCl2 MgCl2(s) ------> Mg^2+(aq) + 2Cl^-(aq) Ionic dissolving 1.0 M ................1.0 M ........ ...2.0 M (Total effect = 3 M) Since the total effect of MgCl2 is the largest, it will lower the vapor pressure the most.

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