propane, C3H8, is common fuel used for cooking and home heating. What massof O2

Question

propane, C3H8, is common fuel used for cooking and home heating. What massof O2 is consumed in the combustion of 1.00g of propane? I am having a hard time getting the balanced equation for this to solve the rest

Explanation / Answer

C3H8 + 5O2---> 3CO2 + 4H2O. First you need to balance the combustion equation as shown above. Then, You can use the law of constant proportions to surmise that for every 1 mol of C3H8 for every 5 mol O2. 1mol C3H8--> 44g 1 mol O2---> 32g x 5= 160 44g/160g=1g/xg, This equates to 160g/44g= 40/11 =3.63g, using significant figures.

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