NaOH + CO2 ---------- Na2CO3 + H2O when 1.85 moles of NaOH is mixed with 1 mole

Question

NaOH + CO2 ---------- Na2CO3 + H2O

when 1.85 moles of NaOH is mixed with 1 mole of co2

a) which is limiting reactant ?

b) how many moles of Na2CO3 can be produced ?

c) how many moles of excess reactant remain after the complitation of reaction ?

Explanation / Answer

1) write bal. rxn.: 2 NaOH + CO2 -----> Na2CO3 + H2O 2) from bal. rxn., 1 mole CO2 reacts with 2 moles NaOH, therefore NaOH is limiting reactant. 3) from bal. rxn., 1 mole of Na2CO3 are made per 2 moles NaOH (1:2) 1.85 moles NaOH x 1/2 moles Na2CO3= 0.925 moles Na2CO3 are produced 4) 1.85 moles NaOH would require 0.925 moles CO2 1.000 moles CO2 at start - 0.925 moles CO2 consumed= 0.075 moles CO2 remain

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