Use the half-reaction shown below to set up the concentration cell as illustrate

Question

Use the half-reaction shown below to set up the concentration cell as illustrated:
Fe2+(aq) + 2e- --> Fe(s) E^o=-0.44 V

There are Fe(s) electrodes in both beakers. There is also a salt bridge joining the two beakers and a voltmeter to measure the potential of this concentration cell, at 25 degrees Celcius.
The beaker on the left contains: [Fe2+]=1.0 M
The beaker on the right contains: [Fe2+]=0.75 M

The initial potential of this concentration cell will be _______
options:
-0.004 v
-0.440 v
-0.024 v
-0.007 v
-0.000 v

Electrons will flow:
-From the right beaker to the left beaker
-From the left beaker to the right beaker
-There will be no flow of electrons

Explanation / Answer

-0.024 v -From the left beaker to the right beaker

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