The Ka of CH3COOH is 1.8 x 10-5. What is [OH-] in a 0.153 M solution of CH3COOH
ID: 745918 • Letter: T
Question
The Ka of CH3COOH is 1.8 x 10-5. What is [OH-] in a 0.153 M solution of CH3COOH ?Explanation / Answer
CH3COOH + H20 ----> CH3COO^- + H30 S 0.153M C -X...........................+X.........… E0.153-X......................+X......… Ka = 1.8E-5 1.8E-5 = [CH3COO^-][H3O^+] / [CH3COOH] 1.8E-5 = (X)^2/ (0.153-X) Assume x is small 1.8E-5 = X^2/0.153 X = 1.65E-3 = [H30^+] use Eqn, [H3O^+][OH^-] = 1.0E-14 [OH^-] = 1.0E-14/[1.65E-3] [OH^-] = 6.02E-12 (the correct answer) P.S the answer you got, was for the H30^+ but they are asking for [OH^-], so use the eqn [OH^-][H30^+] = 1.0E-14
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