please solve and show calculations in the following reaction, what is oxidized a

Question

please solve and show calculations in the following reaction, what is oxidized and what is reduced? also include the change in oxidation numbers for what is oxidized and what is reduced. 6H2SO4 + 2Al ------> Al2(SO4)3 + SO2 + 6H2O

Explanation / Answer

6H2SO4 + 2Al ------> Al2(SO4)3 + SO2 + 6H2O...... from reactant single sulfur in H2SO4 has oxidatio state=+6.... where as in product it have +6 & +4.... so there is reduction of sulfur here & aluminium act as a reducing agent... on other side in reactants Al has O.S=zero & in product has single Al= +3..ie oxidation of Al..

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