The following data were measure for the reactionBF 3(g) + NH 3(g) -----> F 3 BNH
ID: 75101 • Letter: T
Question
The following data were measure for the reactionBF3(g)+ NH3(g)-----> F3BNH3(g): Experiment [BF3]M [NH3]M InitialRate (M/s) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 A) What is the rate law for the reaction? B) What is the overall order of the reaction? C) What is the vale of the rate constant for thereaction? D) What is the rate when [BF3] = 0.100 M and[NH3] = 0.500 M The following data were measure for the reactionBF3(g)+ NH3(g)-----> F3BNH3(g): Experiment [BF3]M [NH3]M InitialRate (M/s) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 A) What is the rate law for the reaction? B) What is the overall order of the reaction? C) What is the vale of the rate constant for thereaction? D) What is the rate when [BF3] = 0.100 M and[NH3] = 0.500 M Experiment [BF3]M [NH3]M InitialRate (M/s) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 A) What is the rate law for the reaction? B) What is the overall order of the reaction? C) What is the vale of the rate constant for thereaction? D) What is the rate when [BF3] = 0.100 M and[NH3] = 0.500 MExplanation / Answer
This one looks trickier at first glance but it is really stratforward. The rate changes with the same proporcion of eachreactant this means that the rate is dependant on both in a one toone ratio. When claculating this make sure you use thedifference where the concentration of the of the reactant isconstant. A.Rate=k*[BF3] *[NH3] B. this is a second order raction because there are two factorin the rate equation. C. You any values from the row to find the rateconstant. .2130=k*.25*.25 k=3.408 D. rate=3.408*.1*.5 rate=.1704Related Questions
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