Chlorine can be prepared in the laboratory by the reaction of manganese dioxide

Question

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation: MnO2(s)+ 4 HCl(aq) ---> MnCl2(aq)+ 2 H2O(l) + Cl2(g). How much MnO2(s) should be added to excess HCl(aq) to obtain 365mL of Cl2(g) at 25 degree celsius and 785 Torr? Please show your work. I would like to see how the problem was solved.

Explanation / Answer

MnO2 + 4HCl --> MnCl2 + 2H2O + Cl2 1. find moles Cl2 produced using pv=nrt n = pv/rt n = 0.86atm x 0.275L / 0.0821L-atm/mole-K x 278K n = 0.01moles Cl2 2. find g MnO2 required gMnO2 = 0.01moles Cl2 x (1MnO2 / 1Cl2) x 86.94g/mole = 0.87gMnO2

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