The Keq for the equilibrium below is 7.52 x 10^-2 at 480degrees C. 2Cl2(g) + 2H2

Question

The Keq for the equilibrium below is 7.52 x 10^-2 at 480degrees C. 2Cl2(g) + 2H2O(g) <=> 4 HCl(g) + O2(g) What is the value of Keq at this temp. for the followingrxn: 2HCl(g) + 1/2 O2(g) <=> Cl2(g) + H2O(g) (a) -0.0376 (b) 5.66 x 10^-3 (c) 13.3 (d) 0.274 (e) 3.65 The Keq for the equilibrium below is 7.52 x 10^-2 at 480degrees C. 2Cl2(g) + 2H2O(g) <=> 4 HCl(g) + O2(g) What is the value of Keq at this temp. for the followingrxn: 2HCl(g) + 1/2 O2(g) <=> Cl2(g) + H2O(g) (a) -0.0376 (b) 5.66 x 10^-3 (c) 13.3 (d) 0.274 (e) 3.65

Explanation / Answer

2Cl2 + 2 H2O 4HCl + O2

Keq =    [HCl]4[O2]/[Cl2]2[H2O]2

2HCl + 1/2 O2 Cl2 +H2O

K/eq = [Cl2][H2O]/[HCl]2[O2]1/2

                                                                                                                                                                        

    K/eq =1/Keq1/2

            

           = 1/ [7.52*10-2]1/2

            = 3.646

             ˜3.65

So the option   e   is correctanswer

                         

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.