calculate (Triangle G degree R) for the following reaction: C2H2 (g) + H2 (g) --

Question

calculate (Triangle G degree R) for the following reaction: C2H2 (g) + H2 (g) --> C2H4 (g)

Explanation / Answer

First thing you should do is write the balanced combustion equations out Hc (1) C2H4 + 3O2 -> 2CO2 + 2H20 -1411 kjmol-1 (2) H2 + (1/2)O2 -> H2O 1286 kjmol-1 (3) C2H6 + (7/2)O2 -> 2CO2 + 3H20 -1560 kjmol-1 Now take a look at the reaction you are calculating the Enthalpy for: C2H4 (g) +H2 (g) -> C2H6 (g) What you want to do is sum the combustion equations in a way that will give you this equation: (1) + (2) - (3) +(1) C2H4 + 3O2 -> 2CO2 + 2H20 +(2) H2 + (1/2)O2 -> H2O -(3)2CO2 + 3H20 -> C2H6 + (7/2)O2 Product: C2H4 (g) +H2 (g) -> C2H6 (g) Now apply this to the combustion enthalpies : (1) + (2) - (3) (-1411 kjmol-1) + (1286 kjmol-1) - (-1560 kjmol-1) = Answer: 1435 kjmol-1

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