2NO + O2 --> 2NO3 Kp=19.2 @ 25 degrees Celsius A)Write the equilibrium expressio

Question

   2NO + O2 --> 2NO3    Kp=19.2 @ 25 degrees Celsius A)Write the equilibrium expression for the reaction B) In the reaction mixture at equilibrium, the partialpressure of NO3 is 9.28torr and that of Br2 is 2.74torr. Find thepartial pressure of NO in this mixture. C)A reaction mixture contains 1.22torr of NO, 0.92torr of O2and 6.31torr of NO3. Is the reaction in equilibrium? Which way willit shift? *lifesaver rating, im so confused, exam tomorrow    2NO + O2 --> 2NO3    Kp=19.2 @ 25 degrees Celsius A)Write the equilibrium expression for the reaction B) In the reaction mixture at equilibrium, the partialpressure of NO3 is 9.28torr and that of Br2 is 2.74torr. Find thepartial pressure of NO in this mixture. C)A reaction mixture contains 1.22torr of NO, 0.92torr of O2and 6.31torr of NO3. Is the reaction in equilibrium? Which way willit shift? *lifesaver rating, im so confused, exam tomorrow

Explanation / Answer

A) All you have to do is use KP = partial pressure of productsmolarcoefficients / partial pressure of reactantsmolarcoefficients In other words, Kp is the partial pressure of eachproduct raised to its molar coeff divided by the partial pressureof each reactant raised to its molar coeff, like so: Kp = PNO32 / (PNO2)(PO2) B) Now just rearrange to solve for PNO3 and plug in! Kp = PNO32 / (PNO2)(PO2) -->PNO2 = PNO32 / (Kp)(PO2) =(9.28)2/(19.2)(2.74) = 1.64. Now take the square root.1.28 torr ***I'm guessing you meant O2 not Br2 in partB C) To find out if it's at equilibrium, you have to use the equationfrom part A and plug in. Kp = PNO32 / (PNO2)(PO2) = (6.312) /(1.222)(.92) = 29.08 torr. This number is higher thanKp [Remember Kp=19.2--it was given in theproblem] That means that there is too much of the products. If this numberwas less than Kp it would mean there's not enough of theproducts. You can tell by looking at how to find Kp[It's the products/reactants]. So in this case, since there is too much of the products,equilibrium will shift left to favor formation of the reactants sothat more reactants can be made to balance out the products. Make sense?

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