The phosphofructokinase reaction in GLYCOLYSIS is: Fructose-6-P + ATP ? Fructose

Question

The phosphofructokinase reaction in GLYCOLYSIS is: Fructose-6-P + ATP ? Fructose-1,6-bisphosphate + ADP + H+ The standard state free energy change for this reaction is -14,200 J/mol. a) Calculate the standard state free energy of HYDROLYSIS of fructose-1,6-bisphosphate to fructose-6-P.. (I think here ATP hydrolysis is -30.5kj/mole). I'm so confused between glycolysis and hydrolysis. b) The human red blood cell concentrations of various metabolites are: [ATP] = 1.85 mM, [ADP] = 0.14 mM, [fructose-6-P] = 0.014 mM, [fructose-1,6-bisphosphate] = 0.031 mM What is the cellular free energy change for the phosphofructokinase reaction at 37

Explanation / Answer

A)The enzyme Phosphofructokinase (PFK) catalyzes the conversion of fructose 6-phosphate (F6P) to fructose 1, 6-bisphosphate (FBP), in step 3 of glycolysis. phosphofructokinase fructose 6-phosphate + ATP-----------------------------> fructose 1,6-bisphosphate + ADP ?G°=-3.4 kcal/mol b)?G = ?G°+ RT ln[products]/[reactants] ?G = - 3.4 kcals/mole + 0.61 kcals/mole ln [F6P] [ATP]/[FBP] [ADP] ?G = - 3.4 kcals/mole + 0.61 kcals/mole ln [.028 mM] [0.2 mM]/[.014 mM] [2 mM] ?G= - 4.38 ?G = - 3.4 + 0.61 ln (0.2) ?G= - 4.38 c) Keq=(ATP)(AMP)/(ADP)²=0.44

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